Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $4x^{2} + 11x + 10 = 0$

(D) Comparing the given equation $4x^{2} + 11x + 10 = 0$ with the standard form $ax^{2} + bx + c = 0$,we get:
$a = 4, b = 11, c = 10$
The discriminant $D$ is given by the formula $D = b^{2} - 4ac$.
Substituting the values:
$D = (11)^{2} - 4(4)(10)$
$D = 121 - 160$
$D = -39$
Since $D < 0$,the quadratic equation has no real roots.